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Part of Quantitative Aptitude > 01 Number System - 25 questions, about 25 min, with an explanation after every answer.
Number System MCQ – Part 3 is a topic inside Quantitative Aptitude (01 Number System). It runs 25 untimed MCQs - roughly 25 min - and the review explains every answer once you submit.
The shape of the set before you start it.
Number System MCQ – Part 3 sits inside Quantitative Aptitude, under the 01 Number System lane, and the portal keeps it as one self-contained set: 25 questions, four options each, no clock and a written explanation behind every answer.
Attempt it once to find the gaps, read why each distractor is wrong, then retake the same set a few days later. The questions you miss twice are the ones worth writing down.
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Read the question, pick an option, then open the answer.
Which of the following numbers is prime?
Answer: (C) 127
Explanation: For 127, test only the primes 2, 3, 5, 7 and 11, since √127 is less than 12. None divides it, so 127 is prime.
The five-digit number 4a7b2 is divisible by 36. What is the greatest possible value of a + b?
Answer: (A) 14
Explanation: Divisibility by 4 requires b to be odd. The digit sum is 13 + a + b, so a + b must be 5 or 14 for divisibility by 9; 14 is possible with a = 9 and b = 5.
What is the least perfect square divisible by both 24 and 40?
Answer: (D) 3600
Explanation: LCM of 24 and 40 is 120 = 2³ × 3 × 5. Make each exponent even: 2^4 × 3² × 5² = 3600.
Find the sum of the cubes of the first 9 natural numbers.
Answer: (B) 2025
Explanation: The sum of cubes is the square of the sum: (9 × 10 ÷ 2)² = 45² = 2025.
How many positive factors of 2^5 × 3^4 × 5² are odd multiples of 9?
Answer: (C) 9
Explanation: An odd factor has exponent 0 for 2. The exponent of 3 can be 2, 3 or 4, and that of 5 can be 0, 1 or 2, giving 3 × 3 = 9 factors.
What is the unit digit of 6^125 + 8^42?
Answer: (A) 0
Explanation: Every positive power of 6 ends in 6. Since 42 leaves remainder 2 on division by 4, 8^42 ends in 4; 6 + 4 = 10 gives unit digit 0.
What is the smallest five-digit number exactly divisible by 27?
Answer: (D) 10017
Explanation: 10000 = 27 × 370 + 10. Add 27 − 10 = 17 to obtain 10017.
A number leaves remainder 17 when divided by 28. What remainder does it leave when divided by 7?
Answer: (B) 3
Explanation: Write the number as 28q + 17. Since 28q is divisible by 7, the remainder is that of 17 ÷ 7, namely 3.
Find the remainder when 3^100 is divided by 17.
Answer: (C) 13
Explanation: 3^4 = 81 leaves remainder 13, and 3^8 leaves remainder −1 modulo 17, so 3^16 leaves remainder 1. Since 100 = 16 × 6 + 4, the required remainder is 13.
Evaluate 998 × 1002.
Answer: (D) 999996
Explanation: Use (1000 − 2)(1000 + 2) = 1000² − 2² = 1000000 − 4 = 999996.
What is the greatest digit x for which 6x34 is divisible by 6?
Answer: (B) 8
Explanation: The last digit is even, so only divisibility by 3 remains. The digit sum 13 + x is a multiple of 3 for x = 2, 5 or 8; the greatest is 8.
How many integers n satisfy 20 < √n < 21?
Answer: (A) 40
Explanation: Squaring gives 400 < n < 441. The integers from 401 to 440 total 440 − 401 + 1 = 40.
A positive integer has exactly 24 positive factors. Its prime factorisation is 2^a × 3², where a is a non-negative integer. Find a.
Answer: (C) 7
Explanation: The factor count is (a + 1)(2 + 1) = 24. Hence a + 1 = 8 and a = 7.
In an arithmetic progression, the first term is 8 and the common difference is 6. Which term is 152?
Answer: (D) 25
Explanation: Solve 8 + (n − 1) × 6 = 152. Thus n − 1 = 24 and n = 25.
What are the last two digits of 3^40?
Answer: (B) 01
Explanation: 3^10 ends in 49, so 3^20 ends in 49² = 2401, hence in 01. Squaring again shows that 3^40 also ends in 01.
The sum of the first n positive even integers is 870. Find n.
Answer: (A) 29
Explanation: The sum is n(n + 1), so n(n + 1) = 870 = 29 × 30. Therefore n = 29.
How many consecutive positive integers n satisfy that n! has exactly 24 trailing zeros?
Answer: (C) 5
Explanation: 100! has 20 + 4 = 24 trailing zeros, and the count stays 24 through 104!. At 105! it becomes 21 + 4 = 25, so there are 5 values.
What is the least positive integer that leaves remainder 2 when divided by 5 and remainder 3 when divided by 7?
Answer: (D) 17
Explanation: Numbers leaving remainder 2 on division by 5 begin 2, 7, 12, 17. The first of these leaving remainder 3 on division by 7 is 17.
If x + 1/x = 5 and x ≠ 0, find x³ + 1/x³.
Answer: (B) 110
Explanation: Use x³ + 1/x³ = (x + 1/x)³ − 3(x + 1/x). The value is 5³ − 3 × 5 = 110.
A number is divided by 9, giving quotient q and remainder 7. If the same number is divided by 7, the quotient is q + 4 and the remainder is 1. Find the number.
Answer: (A) 106
Explanation: Equate the two forms: 9q + 7 = 7(q + 4) + 1. Thus 2q = 22, q = 11 and the number is 9 × 11 + 7 = 106.
Using each of the digits 0, 4, 7 and 8 exactly once, what is the greatest four-digit number divisible by 4?
Answer: (C) 8740
Explanation: The first two digits can be 87, leaving 4 and 0. Both 40 and 04 are divisible by 4, and 8740 is the greater arrangement.
A three-digit number has hundreds digit 3 more than its units digit. Its tens digit is twice its units digit, and its digit sum is 19. Find the number.
Answer: (D) 784
Explanation: Let the units digit be u. Then (u + 3) + 2u + u = 19, giving u = 4; the digits are 7, 8 and 4.
Find the remainder when 12^35 − 1 is divided by 11.
Answer: (B) 0
Explanation: 12 leaves remainder 1 on division by 11. Therefore 12^35 − 1 leaves remainder 1^35 − 1 = 0.
What is the least positive integer that must be added to 6,700 to obtain a perfect cube?
Answer: (C) 159
Explanation: 18³ = 5832 and 19³ = 6859. The next perfect cube is 6859, so add 6859 − 6700 = 159.
How many ordered digit pairs (a, b) make the four-digit number 5a2b divisible by 15?
Answer: (A) 7
Explanation: For divisibility by 5, b = 0 or 5. If b = 0, a can be 2, 5 or 8; if b = 5, a can be 0, 3, 6 or 9, giving 3 + 4 = 7 pairs.
Where the marks actually come from.
Number System MCQ – Part 3 is factual rather than analytical: you either recall it in seconds or you lose the mark to somebody who did. That makes it one of the cheapest sections to convert - a handful of short sittings usually settles the whole cluster.
Derived from the subject and lane this topic belongs to.
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What an examiner usually reaches for in this cluster.
Expect one-line recall questions - definitions, stand-for expansions, identifiers and the ordering of things. Practise the wording as well as the concept: these papers test terminology, and the set above uses the same four-option shape they do.
20 fresh mixed questions a day, plus the current-affairs sets examiners keep reusing.
How this topic behaves in real papers.
Past papers reuse clusters like this almost verbatim across years and posts. Run the same set until every distractor is familiar - previous-year style questions stop being recall and start being free marks.
The portal's previous-year practice runs through the General Knowledge lane and the daily mixed quiz.
Neighbouring sets in this subject, then the rest of the portal.
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From General Knowledge
25 MCQs
From General Knowledge
25 MCQs
25 questions, about 25 min, instant scoring and a full review at the end.
Answered against the set as it is published today.
Number System MCQ – Part 3 runs 25 untimed questions - about 25 min at a steady pace. The set clears at 40% and you can retake it as often as you like.
The set answers that: each question carries four options and a full explanation, so you learn the wording an examiner uses, not just the fact behind it.
Open the quiz page above, or start from the Quantitative Aptitude subject page if you want to drill neighbouring lanes in the same sitting.
Scores, bookmarks and streaks need the optional Google sign-in. Opening the set and answering questions does not.