Punjab Police Constable
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Part of Reasoning > 01 Number Series - 25 questions, about 25 min, with an explanation after every answer.
Number Series MCQ – Part 3 is a topic inside Reasoning (01 Number Series). It runs 25 untimed MCQs - roughly 25 min - and the review explains every answer once you submit.
The shape of the set before you start it.
Number Series MCQ – Part 3 sits inside Reasoning, under the 01 Number Series lane, and the portal keeps it as one self-contained set: 25 questions, four options each, no clock and a written explanation behind every answer.
Attempt it once to find the gaps, read why each distractor is wrong, then retake the same set a few days later. The questions you miss twice are the ones worth writing down.
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Read the question, pick an option, then open the answer.
Choose the missing value in 35, 50, 63, 82, 99, ?.
Answer: (B) 122
Explanation: The terms are 6² − 1, 7² + 1, 8² − 1, 9² + 1, 10² − 1. Next is 11² + 1 = 122.
An alternating rise-and-fall pattern gives 28, 30, 27, 31, 26, 32, ? . What follows?
Answer: (A) 25
Explanation: The changes are +2, −3, +4, −5, +6, then −7. Hence 32 − 7 = 25.
The sequence 3, 5, 9, 16, 28, 48, ? adds a small increasing adjustment to a two-term sum. Find its next term.
Answer: (D) 81
Explanation: Add the previous two terms and then 1, 2, 3, 4, 5 successively. The next term is 28 + 48 + 5 = 81.
Fill the blank in 2, 8, 72, ?, 28800, using the pattern of multipliers.
Answer: (D) 1152
Explanation: Multiply by 2², 3², 4², 5². The blank is 72 × 16 = 1152; 1152 × 25 = 28800.
For the interwoven list 11, 150, 13, 143, 17, 136, 19, 129, ... , which number occupies position 11?
Answer: (B) 29
Explanation: Odd positions contain consecutive primes 11, 13, 17, 19, 23, 29. Position 11 is the sixth odd-position term, so it is 29.
Kirandeep obtains 4, 18, 8, 30, 14, 48, 23, ? by alternating two rules. Determine the missing value.
Answer: (B) 75
Explanation: Alternate ×3 + 6 and ÷2 − 1. After 48 ÷ 2 − 1 = 23, apply 23 × 3 + 6 = 75.
A token series starts 38, 49, 60, 71 and ends at 170 with the same gap. How many tokens are in the series, including both ends?
Answer: (C) 13
Explanation: There are (170 − 38) ÷ 11 = 12 gaps. Including the first token gives 12 + 1 = 13 tokens.
If the bases are consecutive primes starting at 3, which number fits 12, 30, 56, 132, 182, ?
Answer: (B) 306
Explanation: Each term is p(p + 1) for p = 3, 5, 7, 11, 13. Next p = 17, giving 17 × 18 = 306.
Find the faulty entry in 8, 10, 27, 14, 64, 22, 126, 38, 216, 70.
Answer: (D) 126
Explanation: Odd positions should be 2³, 3³, 4³, 5³, 6³, so 126 should be 125. Even-position gaps are 4, 8, 16, 32, confirming that strand.
Recognise the bases in 4, 9, 25, 64, 144, ? and supply the next number.
Answer: (C) 289
Explanation: The square bases are 2, 3, 5, 8, 12, with gaps 1, 2, 3, 4. The next base is 17, giving 17² = 289.
The successive multipliers are −2, +3, −4, +5, −6. Complete 3, −6, −18, 72, 360, ?.
Answer: (B) -2160
Explanation: The final multiplier is −6. Therefore 360 × (−6) = −2160.
Find the next output of the rule hidden in 4, 10, 23, 51, 109, ?.
Answer: (C) 229
Explanation: Double and add successive primes 2, 3, 5, 7, 11. Thus 109 × 2 + 11 = 229.
The jumps grow rapidly in 11, 13, 19, 43, 163, ? . Which term follows?
Answer: (D) 883
Explanation: The gaps are 2!, 3!, 4!, 5!, then 6!. Thus 163 + 720 = 883.
A puzzle combines 6, 8, 12, 16, 20, 32, 30, 64, ?, ? . Select the ordered pair that continues it.
Answer: (A) (42, 128)
Explanation: Odd positions are 2×3, 3×4, 4×5, 5×6, then 6×7 = 42. Even positions double, so 64 × 2 = 128.
From the third entry onward, add the previous two entries and then add 3. What fills the blank in 4, 9, 16, 28, 47, ?
Answer: (A) 78
Explanation: Use 28 + 47 + 3 = 78.
Which value continues 17, 43, 89, 161, 265, ? when each term combines a square and the preceding integer’s cube?
Answer: (D) 407
Explanation: The rule is n² + (n − 1)³ for n = 3, 4, 5, 6, 7. Next is 8² + 7³ = 64 + 343 = 407.
Complete the multiplication chain 2, 18, ?, 630, 1890, 1890.
Answer: (B) 126
Explanation: The multipliers descend through odd numbers 9, 7, 5, 3, 1. Hence 18 × 7 = 126, followed by 126 × 5 = 630.
Amandeep repeats the cycle +7, ×2, −5. Starting with 9, he gets 9, 16, 32, 27, 34, 68, ? . Find the next entry.
Answer: (C) 63
Explanation: After +7 and ×2, the third operation is −5. Thus 68 − 5 = 63.
One quotient has been misprinted in 46080, 23040, 5760, 960, 125, 12. Which quotient is wrong?
Answer: (C) 125
Explanation: Divide by 2, 4, 6, 8, 10 in order. The fifth term must be 960 ÷ 8 = 120 and then 120 ÷ 10 = 12, so 125 is wrong.
After 24, 29, 38, 52, 57, 66, 80, what are the next two entries when the gap cycle repeats?
Answer: (A) (85, 94)
Explanation: The gap cycle is +5, +9, +14. After 80, add 5 and then 9 to get 85 and 94.
The descending consecutive primes are 73, 71, ?, 61, ?, 53. What is the sum of the two missing primes?
Answer: (C) 126
Explanation: The missing primes are 67 and 59. Their sum is 67 + 59 = 126.
The terms 36, 80, 150, 252, 392, ? follow n³ + n². Determine the missing term.
Answer: (A) 576
Explanation: The bases are 3, 4, 5, 6, 7, then 8. Therefore 8³ + 8² = 512 + 64 = 576.
Supply the final value in 4, 22, 91, 278, 563, ? by tracking multipliers and additions separately.
Answer: (C) 574
Explanation: The rules are ×5 + 2, ×4 + 3, ×3 + 5, ×2 + 7. Next is ×1 + 11, so 563 + 11 = 574.
Compare successive ratios in 96, 144, 288, 720, 2160, ? . Which value continues the pattern?
Answer: (D) 7560
Explanation: The multipliers are 1.5, 2, 2.5, 3, then 3.5. Thus 2160 × 3.5 = 7560.
Find the missing pair in 2, 200, 3, 199, 8, 191, 19, 164, 46, 100, ?, ?.
Answer: (A) (111, -25)
Explanation: Odd positions use next = 2 × latest + older, giving 2 × 46 + 19 = 111. Even positions subtract 1³, 2³, 3³, 4³, then 5³, giving 100 − 125 = −25.
Where the marks actually come from.
Number Series MCQ – Part 3 is factual rather than analytical: you either recall it in seconds or you lose the mark to somebody who did. That makes it one of the cheapest sections to convert - a handful of short sittings usually settles the whole cluster.
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What an examiner usually reaches for in this cluster.
Expect one-line recall questions - definitions, stand-for expansions, identifiers and the ordering of things. Practise the wording as well as the concept: these papers test terminology, and the set above uses the same four-option shape they do.
20 fresh mixed questions a day, plus the current-affairs sets examiners keep reusing.
How this topic behaves in real papers.
Past papers reuse clusters like this almost verbatim across years and posts. Run the same set until every distractor is familiar - previous-year style questions stop being recall and start being free marks.
The portal's previous-year practice runs through the General Knowledge lane and the daily mixed quiz.
Neighbouring sets in this subject, then the rest of the portal.
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From General Knowledge
25 MCQs
From General Knowledge
25 MCQs
25 questions, about 25 min, instant scoring and a full review at the end.
Answered against the set as it is published today.
Number Series MCQ – Part 3 runs 25 untimed questions - about 25 min at a steady pace. The set clears at 40% and you can retake it as often as you like.
The set answers that: each question carries four options and a full explanation, so you learn the wording an examiner uses, not just the fact behind it.
Open the quiz page above, or start from the Reasoning subject page if you want to drill neighbouring lanes in the same sitting.
Scores, bookmarks and streaks need the optional Google sign-in. Opening the set and answering questions does not.